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Compute the standard deviation of any number list — get population and sample SD, variance and mean with the formula explained.
Computing a standard deviation by hand means finding a mean, subtracting it eight or eighty times, squaring, summing, and rooting — tedious and error-prone. The calculator above does it instantly. Follow these steps for a correct result every time.
A quick mental check before you trust any software: with values 2 through 9 averaging 5, deviations of ±4 at most, an SD of 2 feels right — most values sit 1–3 units from the mean. Software agrees; intuition confirmed.
The standard deviation is the most widely used measure of spread (or dispersion) in statistics: it tells you, in a single number, how far data points typically stray from their mean. A small SD means the values huddle near the average; a large SD means they scatter widely. Because it is expressed in the original units — centimeters, dollars, points — it is directly interpretable in a way its squared sibling, the variance, is not.
Two versions exist because two situations exist. The population standard deviation (σ) describes a complete dataset — every student in the class, every widget produced today — and divides the sum of squared deviations by N, the number of values. The sample standard deviation (s) estimates the spread of a larger population from a subset, and divides by N−1 instead of N. That −1 is Bessel’s correction: a sample’s values cluster slightly tighter around their own mean than around the true population mean, so dividing by the smaller N−1 inflates the result just enough to remove the bias. With large N the difference is negligible; with N = 8 it matters.
The SD’s deepest connection is to the normal distribution, the bell curve that models heights, measurement errors, and countless natural quantities. The empirical rule (68–95–99.7) says that for normal data, about 68% of values lie within one SD of the mean, 95% within two, and 99.7% within three. This turns the SD into a universal ruler: a z-score of z = (x − μ)/σ tells you exactly how many SDs a value sits from the mean, letting you compare a 92 on one exam (μ = 75, σ = 8, z = 2.125) with a 410 on another (μ = 350, σ = 40, z = 1.5) — the first performance is more exceptional.
The concept crystallized in the 19th century. Gauss used root-mean-square deviations in his theory of errors; Karl Pearson coined the term “standard deviation” and the symbol σ in 1894. Squaring the deviations — rather than averaging absolute values — won out because squares are smooth and differentiable (calculus-friendly), penalize large errors heavily (one wild outlier counts quadratically), and arise naturally in the mathematics of the normal curve and least-squares fitting.
Today the SD is everywhere: finance uses it as the definition of volatility and risk; manufacturing tracks it for quality control (Six Sigma aims for tiny variation); education uses it to curve grades fairly; science reports every measurement as value ± SD; and machine learning standardizes features by subtracting the mean and dividing by the SD before training. Whenever someone quotes an average without a spread, you are only hearing half the story.
Both formulas share the same skeleton — root of the mean squared deviation — and differ only in the denominator:
Population: σ = √(Σ(x − μ)² / N)
Sample: s = √(Σ(x − x̄)² / (N−1))
Read it inside-out: subtract the mean from each value (the deviations), square each deviation (so negatives don’t cancel), average the squares (this average is the variance), then take the square root (returning to original units). The square root is not cosmetic — variance is in squared units (square-dollars, square-points), which nobody can picture; the SD restores interpretability.
Step 1 — mean: μ = (2+4+4+4+5+5+7+9)/8 = 40/8 = 5. Step 2 — deviations: −3, −1, −1, −1, 0, 0, 2, 4. Step 3 — squared deviations: 9, 1, 1, 1, 0, 0, 4, 16. Step 4 — sum of squares: 9+1+1+1+0+0+4+16 = 32. Step 5 — population variance: σ² = 32/8 = 4. Step 6 — population SD: σ = √4 = 2. If these eight numbers are a sample, the sample variance is 32/7 ≈ 4.5714 and s = √4.5714 ≈ 2.1381 — slightly larger, exactly as Bessel’s correction intends.
Step 1 — mean: x̄ = (10+12+14+16+18)/5 = 70/5 = 14. Step 2 — deviations: −4, −2, 0, 2, 4. Step 3 — squares: 16, 4, 0, 4, 16; sum = 40. Step 4 — sample variance: s² = 40/(5−1) = 40/4 = 10. Step 5 — sample SD: s = √10 ≈ 3.1623. For comparison, the population SD would be √(40/5) = √8 ≈ 2.8284. Notice the symmetry shortcut: evenly spaced data gives symmetric deviations, so you only need to compute half of them.
A teacher gives a quiz to 10 students with scores 68, 72, 75, 78, 80, 82, 85, 88, 90, 92 and wants to know whether the class performed consistently. Sum: 810; mean μ = 81. Deviations: −13, −9, −6, −3, −1, 1, 4, 7, 9, 11. Squared: 169, 81, 36, 9, 1, 1, 16, 49, 81, 121; total 564. Population variance = 564/10 = 56.4, so σ = √56.4 ≈ 7.51 points.
Interpretation: a typical score lands about 7.5 points from the 81 average. By the empirical rule, roughly 68% of scores should fall within 81 ± 7.51, i.e., 73.5 to 88.5 — counting the data, scores 75, 78, 80, 82, 85, 88 qualify (6 of 10 = 60%, close to 68% for such a small set). The teacher can report: “Mean 81, SD 7.5 — solid, consistent performance with no extreme outliers.” A z-score check flags nobody: the lowest score 68 has z = (68−81)/7.51 ≈ −1.73, well within normal bounds.
Two funds each averaged 8% annual return over five years. Fund A returned 8, 9, 7, 10, 6 (%). Fund B returned 15, −5, 20, −10, 20 (%). Same mean — wildly different rides.
Fund A: deviations from 8 are 0, 1, −1, 2, −2; squares 0, 1, 1, 4, 4 sum to 10; sample variance = 10/4 = 2.5; s = √2.5 ≈ 1.58%. Fund B: deviations 7, −13, 12, −18, 12; squares 49, 169, 144, 324, 144 sum to 830; sample variance = 830/4 = 207.5; s = √207.5 ≈ 14.40%. The SD exposes what the mean hides: Fund B’s volatility is nine times Fund A’s. In finance this number is risk — a retiree needing steady income chooses A; a speculator chasing upside tolerates B. Two datasets, identical averages, opposite stories: that is why the standard deviation exists.
Spread is one chapter of the statistics story — read the rest with these tools. The Statistics Calculator gives the full descriptive summary (mean, median, mode, range, variance, SD) in one shot; the Mean / Median / Mode Calculator focuses on centers; the Probability Calculator handles the odds behind z-scores; the Z-Score Calculator standardizes any value against its distribution; and the Confidence Interval Calculator turns an SD into a margin of error. Browse the shelf in Math Calculators.
This page provides a standard deviation calculator for a list of numbers. Method: compute the mean, then population variance σ² = Σ(x−μ)²/N and sample variance s² = Σ(x−x̄)²/(N−1); SDs are their square roots. Outputs: count, mean, population variance and SD (σ), sample variance and SD (s). Verified numeric facts: for 2,4,4,4,5,5,7,9, mean 5, Σ squared deviations 32, σ² = 4, σ = 2, s² ≈ 4.5714, s ≈ 2.1381; for 10,12,14,16,18, mean 14, s² = 10, s ≈ 3.1623, σ ≈ 2.8284; quiz scores 68–92 give μ = 81, σ ≈ 7.51; Fund A (8,9,7,10,6) s ≈ 1.58% vs Fund B (15,−5,20,−10,20) s ≈ 14.40% at identical 8% means. Inputs accept comma/space/newline-separated decimals and negatives.
Sources: OpenStax, Introductory Statistics (spread); NIST/SEMATECH e-Handbook of Statistical Methods; Karl Pearson (1894) on the term “standard deviation.” All numerical examples were computed by hand and cross-checked against the calculator.
Find the mean, subtract it from each value, square the differences, average them (÷N for population), then square-root. For 2,4,4,4,5,5,7,9: σ = 2.0.
Population (÷N) when data is the entire group; sample (÷N−1) when estimating a larger group.
How spread out numbers are.
No — always ≥ 0.
The square of the standard deviation (σ²).
Mean = 40/8 = 5. Squared deviations: 9, 1, 1, 1, 0, 0, 4, 16; sum = 32. Population variance = 32/8 = 4, so σ = 2. Sample variance = 32/7 ≈ 4.5714, so s ≈ 2.1381.
Squaring penalizes large deviations more, keeps everything differentiable for calculus, and connects to the normal distribution and least squares. Absolute deviations give the mean absolute deviation — a different, less common measure.
There is no universal ‘good’ value — it depends on context. Compare it to the mean via the coefficient of variation (σ/μ): for test scores with μ = 75 and σ = 8, CV ≈ 10.7%, meaning scores cluster fairly tightly.